B^2-3(b+2)=4

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Solution for B^2-3(b+2)=4 equation: 



^2-3(B+2)=4

We move all terms to the left:

^2-3(B+2)-(4)=0

determiningTheFunctionDomain
-3(B+2)-4+^2=0

We add all the numbers together, and all the variables

-3(B+2)=0

We multiply parentheses

-3B-6=0

We move all terms containing B to the left, all other terms to the right

-3B=6

B=6/-3

B=-2

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